2cos^2(3x)+3cos(3x)+1=0

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Solution for 2cos^2(3x)+3cos(3x)+1=0 equation:


Simplifying
2cos2(3x) + 3cos(3x) + 1 = 0

Remove parenthesis around (3x)
2cos2 * 3x + 3cos(3x) + 1 = 0

Reorder the terms for easier multiplication:
2 * 3cos2 * x + 3cos(3x) + 1 = 0

Multiply 2 * 3
6cos2 * x + 3cos(3x) + 1 = 0

Multiply cos2 * x
6cos2x + 3cos(3x) + 1 = 0

Remove parenthesis around (3x)
6cos2x + 3cos * 3x + 1 = 0

Reorder the terms for easier multiplication:
6cos2x + 3 * 3cos * x + 1 = 0

Multiply 3 * 3
6cos2x + 9cos * x + 1 = 0

Multiply cos * x
6cos2x + 9cosx + 1 = 0

Reorder the terms:
1 + 9cosx + 6cos2x = 0

Solving
1 + 9cosx + 6cos2x = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 9cosx + -1 + 6cos2x = 0 + -1

Reorder the terms:
1 + -1 + 9cosx + 6cos2x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 9cosx + 6cos2x = 0 + -1
9cosx + 6cos2x = 0 + -1

Combine like terms: 0 + -1 = -1
9cosx + 6cos2x = -1

Reorder the terms:
1 + 9cosx + 6cos2x = -1 + 1

Combine like terms: -1 + 1 = 0
1 + 9cosx + 6cos2x = 0

The solution to this equation could not be determined.

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